Refinement of an integral inequality
نویسندگان
چکیده
منابع مشابه
Refinement of an Inequality Of
We prove: Let P(z) = P n k=0 a k z k be a complex polynomial with n 1 and a 0 an 6 = 0. If z is a zero of P, then we have for all real numbers t > 0: (*) jzj > ja 0 jt ja 0 j + Kn(t) with Kn(t) = 1 1 ? n(t) n min 1mn h (n(t) m ? n(t) n) max mpn Ap(t) + (1 ? n(t) m) max 1pn Ap(t) i ; n(t) = ja 0 j ja 0 j + max 1pn Ap(t) ; Ap(t) = 1 p p X k=1 ja k jt k : Inequality (*) sharpens a result of E. Lan...
متن کاملOn an Integral Inequality
In this article we give different sufficient conditions for inequality (∫ b a f(x)dx )β ≥ ∫ b a f(x)dx to hold.
متن کاملOn an Integral Inequality of Feng Qi
In this note, we study a general version of a problem posed by Feng Qi in [10] in the context of a measured space endowed with a positive finite measure. For other studies and results, one can consult the papers [2], [3], [5], [8], [9], [12], [13] and [14]. Our basic tool is the classical Hölder inequality. By the convexity method (see [3]) we give an interpretation of the lower bound occuring ...
متن کاملRefinement of Hardy’s Inequality
We give a simple combinatorial proof of an inequality that refines Hardy’s inequality. As a corollary we obtain a corresponding refinement of Carleman’s inequality.
متن کاملAn Extension of the Hilbert’s Integral Inequality
where the constant factor π 1 is the best possible. This is the famous Hilbert’s integral inequality see 1, 2 . Owing to the importance of the Hilbert’s inequality and the Hilberttype inequality in analysis and applications, some mathematicians have been studying them. Recently, various improvements and extensions of 1.1 appear in a great deal of papers see 3–11 , etc. . Specially, Gao and Hsu ...
متن کاملذخیره در منابع من
با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید
ژورنال
عنوان ژورنال: Journal of Inequalities and Applications
سال: 2012
ISSN: 1029-242X
DOI: 10.1186/1029-242x-2012-103